MATH!!!!!必須於2007年10月17日晚上10時30分前回答!![強烈要求]

3[4(2.5-q)+1]=13-2q
3[10-4q+1]=13-2q
30-12q+3=13-2q
20=10q
q = 2


5(y+4)-6(8+3y)=-2
5y+20-48-18y=-2
20-48+2=13y
-26=13y
y = -2

3[4(2.5-q)+1]=13-2q
3[11-4q+1]=13-2q
3[11-4q]=13-2q
33-12q=13-2q
33-13=-2q+12q
20=10q
2=q
q=2

5(y+4)-6(8+3y)=-2
5y+4-48-19y=-2
-14y-44=-2
-14y=-2+44
-14y=42
y=-3

2007-10-17 10:36:27 補充：
第2條係咁先對:5(y+4)-6(8+3y)=-25y+20-48-19y=-2-14y-28=-2-14y=-2+28-14y=26y=-2

12(2.5-q) + 3 = 13 - 2q
30 - 12q + 3 = 13 - 2q
33 - 13 = -2q + 12q
20 = 10q
q = 2

5y + 20 - 48 - 18y = -2
-13 y -28 = -2
-13y = -2+ 28
-13y = 26
y = -2

3[4(2.5-q)+1]=13-2q
3(10-4q+1)=13-2q
3(11-4q)=13-2q
33-12q=13-2q
20=10q
q=2

5(y+4)-6(8+3y)=-2
5y+20-48-18y=-2
-13y-28=-2
-13y=26
y=-2

3[4(2.5-q)+1]=13-2q
3(10-4q+1)=13-2q
3(11-4q)=13-2q
33-12q=13-2q
-12q+2q=13-33
-10q= -20
q=2 (Answer)


5(y+4)-6(8+3y)=-2
5y+20-48-18y=-2
-13q -28 = -2
-13q = -2+28
-13q =26
q= -2 (Answer)


Hope you will understand !! ^o^

3[4 (2.5-q) + 1] = 13 -2 q
3[10 - 4q +1 ] = 13 - 2q
3[11 - 4q] = 13 - 2q
33 - 12q = 13 -2q
-12q + 2q = 13 -33
-10q = -20
q = -20/-10
q = 2

5(y+4)-6(8+3y) = -2
5y + 20 - 48 - 18y = -2
-13y -28 = -2
-13y = -2 +28
-13y = 26
y = 26 / -13
y = -2

!. 3[4(2.5-q)+1]=13-2q
3[10-10q+1]=13-2q
33-30q=13-2q
20=28q
1.4=q

2. 5(y+4)-6(8+3y)=-2
5y+20-48-18y=-2
-30=13y
1.6=y

3[4(2.5-q)+1]=13-2q=11q

* 5(y+4)-6(8+3y)= -2 <---?

5(y+4)-6(8+3y)=154y

3[4(2.5-q)+1]=13-2q
30-12q+3=13-2q
30+3-13=-2q+12q
20=10q
q=10

5(y+4)-6(8+3y)=-2
5y+20-48-18y=-2
5y-18y=-20+48-2
-13y=26
-y=26
y=-26

2007-10-16 22:23:12 補充：
-y=2y=2

2007-10-16 22:23:41 補充：
q=2

1.
3[4(2.5-q)+1]=13-2q
3[10 - 4q + 1]=13-2q
30 - 12q + 3] = 13 - 2q
30 + 3 -13 = 12q - 2q
40 = 10q
10 = q
q = 10

2.
5(y+4)-6(8+3y)=-2
5y+20-48-18y=-2
-13y=26
y=-2

3[4(2.5-q)+1]=13-2q
3(10-4q+1)=13-2q
3(11-4q)=13-2q
33-12q=13-2q
20=10q
q=2

5(y+4)-6(8+3y)=-2
5y+20-48-18y=-2
-13y-28=-2
-13y=26
y=-2