how to solve it?

👨🏻‍🏫 學術台數學

2007-10-16 8:05 am

｜x｜^2 < 1
..............-
question:absolute ｜x｜^2 less and equal to 1
我唔知點做,有冇人可以教下我?

回答 (2)

2007-10-16 8:25 am

✔ 最佳答案

| x | ^2 <= 1
square root of ( | x | ^2) <= square root of 1
| x | <= 1
x <= 1 and x >= -1
-1 <= x <= 1

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2007-10-21 8:06 am

Solve ｜x｜² ≦ 1.

｜x｜² ≦ 1
x² ≦ 1
-1 ≦ x ≦ 1

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