✔ 最佳答案
1) f ( x ) = x^2 + 2x - 15
若f ( x )可被x+k整除
f ( - k ) = 0
( - k )^2 + 2 ( - k ) - 15 = 0
k^2 - 2k - 15 = 0
( k - 5 )( k + 3 ) = 0
k = 5 或 -3
2) f(x)=ax^3+bx^2-3
f ( 1 ) = 0
a ( 1 )^3 + b ( 1 )^2 - 3 = 0
a + b = 3 --- ( 1 )
f ( - 1 ) = -2
a ( - 2 )^3 + b ( - 2 )^2 - 3 = -2
-8a + 4b - 1 = 0
a = ( 4b - 1 ) / 8 --- ( 2 )
代( 2 ) 入(1 ),
( 4b - 1 ) / 8 + b = 3
4b - 1 + 8b = 24
12b = 25
b = 25 / 12
a + 25 / 12 = 3
a = 11 / 12
3) x^2+2x-3 = ( x + 3 )( x - 1 ), 所以
f ( - 3 ) = 0
a ( - 3 )^3 + 4 ( - 3 )^2 + b ( - 3 ) - 6 = 0
-27a + 36 - 3b - 6 = 0
9a + b = 10 --- ( 1 )
f ( 1 ) = 0
a ( 1 )^3 + 4 ( 1 )^2 + b ( 1 ) - 6 = 0
a + b = 2 --- ( 2 )
( 1 ) - ( 2 ) : 8a = 8
a = 1
1 + b = 2
b = 1