6p(2次)+6-4p-9p
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教下我啦! thz...
F.2 maths(very easy ga ja!)
2007-10-16 2:37 am
回答 (6)
2007-10-16 2:43 am
✔ 最佳答案
6p²+6-4p-9p=6p²-4p-9p+6
=2p(3p-2)-3(3p-2)
=(3p-2)(2p-3)
2007-10-16 6:37 am
6P^2-9P-4P+6
=3P(2P-3)-2(2P-3)
=(3P-2)(2P-3)
=3P(2P-3)-2(2P-3)
=(3P-2)(2P-3)
2007-10-16 2:47 am
(6p)(6p)+6-4p-9p
=6p*6p+6-4p-9p
=36p(cube)+6-4p-9p
=36p(cube)-13p+6
=6p*6p+6-4p-9p
=36p(cube)+6-4p-9p
=36p(cube)-13p+6
2007-10-16 2:44 am
6p(2次)+6-4p-9p
6p^2+6-4p-9p
=6p^2-13p+6
=(3p-2)(2p-3)
2007-10-15 18:45:09 補充：
use cross method
6p^2+6-4p-9p
=6p^2-13p+6
=(3p-2)(2p-3)
2007-10-15 18:45:09 補充：
use cross method
參考: me
2007-10-16 2:43 am
6p*6p+6-4p-9p
=36p+6-13p
=23p+6
6的2次就36所以就36p被9p同4p減，就將佢地相加再減，=36p-13p=23p+6
=36p+6-13p
=23p+6
6的2次就36所以就36p被9p同4p減，就將佢地相加再減，=36p-13p=23p+6
參考: me
2007-10-16 2:42 am
因式分解？
收錄日期: 2021-04-13 19:03:12
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20071015000051KK02626