F.2 maths(very easy ga ja!)

2007-10-16 2:37 am

6p(2次)+6-4p-9p
要過程同答案牙!
教下我啦! thz...

回答 (6)

2007-10-16 2:43 am

✔ 最佳答案

6p²+6-4p-9p
=6p²-4p-9p+6
=2p(3p-2)-3(3p-2)
=(3p-2)(2p-3)

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2007-10-16 6:37 am

6P^2-9P-4P+6
=3P(2P-3)-2(2P-3)
=(3P-2)(2P-3)

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2007-10-16 2:47 am

(6p)(6p)+6-4p-9p
=6p*6p+6-4p-9p
=36p(cube)+6-4p-9p
=36p(cube)-13p+6

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2007-10-16 2:44 am

6p(2次)+6-4p-9p

6p^2+6-4p-9p
=6p^2-13p+6
=(3p-2)(2p-3)

2007-10-15 18:45:09 補充：
use cross method

參考: me

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2007-10-16 2:43 am

6p*6p+6-4p-9p
=36p+6-13p
=23p+6

6的2次就36所以就36p被9p同4p減，就將佢地相加再減，=36p-13p=23p+6

參考: me

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2007-10-16 2:42 am

因式分解？

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