Maths question(10points!!!!!!)1day only!!!!!!!!!Help!!!!!!!

2007-10-16 12:17 am
Ouestions:
1) A 2-dight number is divisble by both 2 and 5. Half this number is less than 6 times the tens digit of the number by 4. Find the 2-digit number.

2) There are some chickens and rabbits in a cage. 1/3 of the rabbits were born to have 3 legs. If the total number of heads is 35 and the total number of legs is 90, find the number of
(a) chicken,
(b) rabbit with 4 legs.

回答 (2)

2007-10-16 12:39 am
✔ 最佳答案
1)
Assume that the 2-digit number is AB
Since it is divisible by both 2 and 5, the value of B must be 0
(You know that B is either 5 or 0, but B must be even number because AB is divisible by 2)
Therefore we can rewrite it as A0.
==> The true value of A0 is 10A + 0 = 10A

According to the question,
10A / 2 = 6A - 4
5A = 6A - 4
4 = A

Thus, the 2-digit number is 40

2a)
Let x be the number of chicken while y be the number of rabbits
Total number of heads = 35
Thus,
x + y = 35 -- (1)
Total number of legs is 90
Thus,
2x + 2/3y(4) + 1/3y(3) = 90
2x + 8y/3 + y = 90
6x + 8y + 3y = 270
6x + 11y = 270 -- (2)

From (1)
x = 35 - y -- (3)
Put (3) into (2)
6(35-y) + 11y = 270
210 - 6y + 11y = 270
5y = 60
y = 12
Put y=12 into (3)
x = 35-12
x = 23

Thus, the number of chickens is 23

2b)
From 2a) y = 12
There are 12 rabbits in total
SInce 1/3 have 3 legs, it means 2/3 of rabbits have 4 legs
Therefore,
12 * 2/3
= 8
There are 8 rabbits with 4 legs

2007-10-15 16:41:33 補充:
樓上的答案可能有點問題煩請檢查
參考: I am a Maths tutor
2007-10-16 12:32 am
1)20
2)a)18
b)15
參考: No


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