1-2[3-(x/2-1)]=x/4+1
1/6[1/2(1-2n)+1/3]=n/3
I want the steps plx
MATHS
2007-10-15 5:56 am
回答 (1)
2007-10-15 7:32 am
✔ 最佳答案
1-2[3-(x/2-1)]=x/4+1 1-2[3-x/2+1]=x/4+1
1-6+x-2=x/4+1
-7-1=x/4-x
-8X4=(x/4-x)X4
-32=x-4x
x=32/3
1/6[1/2(1-2n)+1/3]=n/3
[1/2(1-2n)+1/3]=2n
1/2-n+1/3=2n
(1/2+1/3)(6)=(2n+n)(6)
5=18n
n=5/18
收錄日期: 2021-05-03 11:42:40
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20071014000051KK05774