F.4 的 MATHS

2007-10-14 10:24 pm

solve the following quardratic equation
5X (X-2) = (X-2)^2
THZ^^

回答 (3)

2007-10-14 10:32 pm

✔ 最佳答案

5x(x-2)=(x-2)^2
5x(x-2)-(x-2)^2=0
(x-2)(5x-x+2)=0
(x-2)(4x+2)=0
x=2 or -1/2

👍 0 👎 0

2007-10-14 10:36 pm

5X (X-2) = (X-2)^2
5x^2 -10x = x^2 -4x +4
4x^2 -6x -4 = 0
2x^2 -3x -2 = 0
(2x+1)(x-2) = 0
x = 2 or -1/2

參考: myself

👍 0 👎 0

2007-10-14 10:30 pm

5x^2-10x=x^2-4x+4
4x^2-6x-4=0
(2x+1)(2x-4)
x=2/-0.5

👍 0 👎 0