F2MATHS 唔識ar

2007-10-13 11:35 pm
(x^2-y^2)/(2x-2y)÷(3x+3y)/6x

回答 (3)

2007-10-13 11:43 pm
✔ 最佳答案
(x^2-y^2)/(2x-2y)÷(3x+3y)/6x

=(x+y)(x-y)/2(x-y)÷3(x+y)/6x

=(x+y)/2 x 6x/3(x+y)

=(x+y)x/(x+y)

=x
2007-10-13 11:45 pm
(x^2-y^2)/(2x-2y) ÷ (3x+3y)/6x
=(x^2-y^2)/(2x-2y) x 6x/(3x+3y)
=(x+y)(x-y)/2(x-y) x 6x/3(x+y)
=(x+y)/2 x 2x/(x+y)
=x
參考: BY myself
2007-10-13 11:44 pm
= (x+y)(x-y)/(2x-2y) * 6x/(3x+3y)
= [(x+y)/2] * [6x/3(x+y)]
= 1/2 * 6x/3
= 1/2 * 2x
= x


收錄日期: 2021-04-13 13:54:40
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20071013000051KK02724

檢視 Wayback Machine 備份