F2MATHS 唔識ar

2007-10-13 11:35 pm

(x^2-y^2)/(2x-2y)÷(3x+3y)/6x

回答 (3)

2007-10-13 11:43 pm

✔ 最佳答案

(x^2-y^2)/(2x-2y)÷(3x+3y)/6x

=(x+y)(x-y)/2(x-y)÷3(x+y)/6x

=(x+y)/2 x 6x/3(x+y)

=(x+y)x/(x+y)

=x

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2007-10-13 11:45 pm

(x^2-y^2)/(2x-2y) ÷ (3x+3y)/6x
=(x^2-y^2)/(2x-2y) x 6x/(3x+3y)
=(x+y)(x-y)/2(x-y) x 6x/3(x+y)
=(x+y)/2 x 2x/(x+y)
=x

參考: BY myself

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2007-10-13 11:44 pm

= (x+y)(x-y)/(2x-2y) * 6x/(3x+3y)
= [(x+y)/2] * [6x/3(x+y)]
= 1/2 * 6x/3
= 1/2 * 2x
= x

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