F.2 Maths
2007-10-13 6:11 am
化簡 {(2a^2)x + (b^2)y + (2b^2)x + (a^2)y} / {(a^2)x - (5b^2)y + (b^2)x - (5a^2)y}
回答 (3)
2007-10-13 6:22 am
✔ 最佳答案
{(2a^2)x + (b^2)y + (2b^2)x + (a^2)y} / {(a^2)x - (5b^2)y + (b^2)x - (5a^2)y} ={2(a^2+b^2 )x + (b^2 + a^2)y} / {(a^2 + b^2)x - 5(b^2 - a^2)y}
=[(a^2+b^2) (2x+y)] / [(a^2 + b^2) (x-5y)]
=(2x+y) / (x-5y)
2007-10-13 6:40 am
{(2a^2)x + (b^2)y + (2b^2)x + (a^2)y} / {(a^2)x - (5b^2)y + (b^2)x - (5a^2)y}
={2(a^2+b^2 )x + (b^2 + a^2)y} / {(a^2 + b^2)x - 5(b^2 - a^2)y}
=[(a^2+b^2) (2x+y)] / [(a^2 + b^2) (x-5y)]
=(2x+y) / (x-5y)
希望幫到你啦-3-
={2(a^2+b^2 )x + (b^2 + a^2)y} / {(a^2 + b^2)x - 5(b^2 - a^2)y}
=[(a^2+b^2) (2x+y)] / [(a^2 + b^2) (x-5y)]
=(2x+y) / (x-5y)
希望幫到你啦-3-
2007-10-13 6:31 am
= 2x(a^2 + b^2) + y(a^2 + b^2) / x(a^2 + b^2) - 5y(a^2 + b^2)
=(2x + y)(a^2 + b^2) / (x - 5y)(a^2 + b^2)
= 2x + y / x - 5y
=(2x + y)(a^2 + b^2) / (x - 5y)(a^2 + b^2)
= 2x + y / x - 5y
參考: 你這樣打出來很難看，所以我也不肯定有冇mistake
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