✔ 最佳答案
First, we find out the standard deviation (SD):
Standard score, Z (50%-21% i.e. 29%)corresponds to melon weight less than 2.19 kg is -0.805
Therefore, (2.19-3)/SD = -0.8005 and SD = 1.01
Percentage of weight more than 5kg =Probability[(Z>(5-3)/1.01
=Probability (Z>1.98)
=0.5- 0.4761
=0.0239
=2.39%