請大家列出所有因式分解的恆等式
回答 (2)
2007-10-11 7:22 pm
✔ 最佳答案
Not sure if I can list all of the identities, but here are some for your reference:a^2-b^2=(a+b)(a-b)
a^3-b^3=(a-b)(a^2+ab+b^2)
a^3+b^3=(a+b)*(a^2-a*b+b^2)
a^4-b^4=(a-b)(a+b)(a^2+b^2)
a^5+b^5=(a+b)*(a^4-a^3*b+a^2*b^2-a*b^3+b^4)
a^5-b^5=(a-b)*(a^4+a^3*b+a^2*b^2+a*b^3+b^4)
...
2007-10-12 2:51 am
a(d+e)+g(d+e)
=(d+e)(a+g)==
=(d+e)(a+g)==
收錄日期: 2021-04-13 13:51:39
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