解下列方程:
NO1
3(2b-1)-4b=-13
NO2
4t-5(3-2t)=13
NO3
3a-2(2a+5)=-11
NO4
-2y+3(4y-7)=1
NO5
5(m-2)+3=4(3-m)-1
NO6
3(n+6)-5=2(n-2)
NO7
3(2y+1)-2(y-3)=1
NO8
3a-(5a-9)=11-(3a+1)
要步驟.
無限THXTHXTHX
收錄日期: 2021-04-13 13:50:57
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20071010000051KK02640