A.maths
回答 (2)
2007-10-10 2:28 am
✔ 最佳答案
由於問題不清晰，故將2個可能性均做一次。一：∫3-(cot Θ)^2/(cos Θ)^2 dΘ
=3x-∫(cosec Θ)^2 dΘ
=3x+cot Θ +C
二：∫(3-(cot Θ)^2)/(cos Θ)^2 dΘ
=3∫(sec Θ)^2 dΘ - ∫(cosec Θ)^2 dΘ
=3tan Θ + cot Θ + C
2007-10-09 18:29:00 補充：
SORRY, for 一那裏，x是代表Θ，打錯了，sorry
參考: My Mathematics Knowledge
2007-10-09 5:57 am
∫(3-cot^2Θ)/cos^2Θ dΘ
=∫(3sec^2Θ-csc^2Θ) dΘ
=(3tan^2Θ)/2 + (cot^2Θ) /2 +C
=∫(3sec^2Θ-csc^2Θ) dΘ
=(3tan^2Θ)/2 + (cot^2Θ) /2 +C
收錄日期: 2021-04-13 18:11:57
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20071008000051KK04167