factorize the following:
2x(-1+2a)-4x(2+a)
2(2-a)(-1+2a)+4(a-2)(2+a)
F.2 Maths
2007-10-09 5:13 am
回答 (5)
2007-10-09 5:32 am
✔ 最佳答案
1. 2x(-1+2a)-4x(2+a)＝-2-2a-8-4a
=-6-6a
2.2(2-a)(-1+2a)+4(a-2)(2+a)
=2(2+4a+a-2a次方)+4(a次方-4)
=4+10a-8a次方+4a次方-16
=-12+10a-4a次方
2007-10-09 5:15 pm
2x(-1+2a)-4x(2+a)
=2x[(-1+2a)-2(2+a)]
=2x(-1+2a-4-2a)
=2x(-5)
=-10x
2(2-a)(-1+2a)+4(a-2)(2+a)
=2(2-a)(-1+2a)+4[-(2-a)](2+a)←－－Note that a-2 = -(2-a)
=2(2-a)(-1+2a)-4(2-a)(2+a)←－－－Put x = 2-a
=-10(2-a)←－－－－－－－－－Using the result above
=-10[-(a-2)]←－－－－－－－－reduce the negative sign if possible
=10(a-2)
=2x[(-1+2a)-2(2+a)]
=2x(-1+2a-4-2a)
=2x(-5)
=-10x
2(2-a)(-1+2a)+4(a-2)(2+a)
=2(2-a)(-1+2a)+4[-(2-a)](2+a)←－－Note that a-2 = -(2-a)
=2(2-a)(-1+2a)-4(2-a)(2+a)←－－－Put x = 2-a
=-10(2-a)←－－－－－－－－－Using the result above
=-10[-(a-2)]←－－－－－－－－reduce the negative sign if possible
=10(a-2)
2007-10-09 11:10 am
2x(-1+2a)-4x(2+a)
= (-2+4a)-(8+4a)
= -2+4a-8-4a
= -10
2(2-a)(-1+2a)+4(a-2)(2+a)
= (4-2a)(-1+2a)+(4a-8)(2+a)
= (-4+8a+2a-4a^2)+(8a+4a^2-16-8a)
= -4+8a+2a-4a^2+8a+4a^2-16-8a
= 10a-20
= (-2+4a)-(8+4a)
= -2+4a-8-4a
= -10
2(2-a)(-1+2a)+4(a-2)(2+a)
= (4-2a)(-1+2a)+(4a-8)(2+a)
= (-4+8a+2a-4a^2)+(8a+4a^2-16-8a)
= -4+8a+2a-4a^2+8a+4a^2-16-8a
= 10a-20
2007-10-09 6:18 am
2x(-1+2a)-4x(2+a)
=(-2x+4xa)-(8x+4xa)
=-2x+4xa-8x-4xa
=4xa-4xa-2x-8x
=-10x
=(-2x+4xa)-(8x+4xa)
=-2x+4xa-8x-4xa
=4xa-4xa-2x-8x
=-10x
2007-10-09 5:18 am
1.(-2x)+(4xa)-(8x)-(4xa)
(4xa)(-10x)
2.
(4xa)(-10x)
2.
收錄日期: 2021-04-13 13:49:18
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20071008000051KK04009