3,,,The memory capacity of the harddisk in May's computer is 8.5x10^8 byte.The files stored include 3.3x10^8, 8.4*10^7, 2.5x10^7, 8.2x10^6, 1.6x10^6, 3.0x10^8
a, How much space is left in May's harddisk?[1.012x10^8]
b, May sends her files[1.6x10^6] to David. It takes 2.1x10^-5 second to send one byte. How long does it take to send the files[1.6x10^6] to David?[33.6s]
中3~Laws of Indices[要列式]
2007-10-09 5:06 am
回答 (1)
2007-10-09 8:01 am
✔ 最佳答案
3a the used capacity=(3.3x10^8)+ (8.4x10^7)+( 2.5x10^7)+( 8.2x10^6)+( 1.6x10^6)+(3.0x10^8)
=10^6[3.3x100+8.4x10+2.5x10+8.2+1.6+3x100]
=10^6(330+84+25+8.2+1.6+300)
=10^6(748.8)
=10^6(7.488x10^2)
=7.488 x 10^8
so the space is left in May's harddisk
=8.5x10^8 - 7.488x10^8
=10^8(8.5-7.488)
=1.012 x 10^8 byte
b it take
=(1.6x10^6) x (2.1x10^-5)
=(1.6x2.1) x (10^6x10^-5)
=3.36 x10^(6-5)
=3.36 x 10
=33.6
so it take 33.6s to send the files
收錄日期: 2021-04-13 13:49:27
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https://hk.answers.yahoo.com/question/index?qid=20071008000051KK03949