中四函數 求救

By using the completeing square

y = -5(t^2 -2t +1 -1) + 5
........ => t^2 - 2t +1 = (t-1)^2
y = -5[(t-1)^2 - 1] +5
y = -5(t-1)^2 +5 +5
y = -5(t-1)^2 + 10
Therfore, a = -5 , h = 1, k =10

thx

y=-5(t^2-2t)+5
y=-5(t^2-2t+1-1)+5
y=-5(t-1)^2+5+5
y=-5(t-1)^2+10
a=-5,x=t,h=1,k=10

y = -5 ( t^2 - 2t) +5
y=-5(t^2-2t+1-1)+5
y=-5(t-1)^2+10