y = -5 ( t^2 - 2t) +5
化成 y = a(x - h)^2 + k
連步驟 唔該
中四函數 求救
2007-10-08 3:09 am
回答 (4)
2007-10-08 3:17 am
✔ 最佳答案
By using the completeing squarey = -5(t^2 -2t +1 -1) + 5
........ => t^2 - 2t +1 = (t-1)^2
y = -5[(t-1)^2 - 1] +5
y = -5(t-1)^2 +5 +5
y = -5(t-1)^2 + 10
Therfore, a = -5 , h = 1, k =10
參考: Me
2007-12-19 1:00 am
thx
2007-10-08 3:14 am
y=-5(t^2-2t)+5
y=-5(t^2-2t+1-1)+5
y=-5(t-1)^2+5+5
y=-5(t-1)^2+10
a=-5,x=t,h=1,k=10
y=-5(t^2-2t+1-1)+5
y=-5(t-1)^2+5+5
y=-5(t-1)^2+10
a=-5,x=t,h=1,k=10
參考: 自己
2007-10-08 3:12 am
y = -5 ( t^2 - 2t) +5
y=-5(t^2-2t+1-1)+5
y=-5(t-1)^2+10
y=-5(t^2-2t+1-1)+5
y=-5(t-1)^2+10
收錄日期: 2021-04-29 19:40:41
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20071007000051KK04672