勁急 20點 數學LOG數"

2007-10-08 1:01 am
已知X的對數,求X :
(1) lgx = lga + lgb
(2) logaX = logaM - logaN
(3) lgx = 3lgn - lgm
(4) logaX = 0.5logaB - logaC

回答 (1)

2007-10-08 1:16 am
✔ 最佳答案
(1) lgx = lga + lgb
> log x = log (a x b)
> x = a x b

(2) logaX = logaM - logaN
> loga X = loga (M / N)
> X = M/N

(3) lgx = 3lgn - lgm
> log x = (log n^3 - log m)
> log x = log (n^3 / m)
> x = n^3 / m

(4) logaX = 0.5logaB - logaC
> loga X = loga (B^0.5) - loga C
> loga X = loga (B^0.5 / C)
> X = B^0.5 / C or X = √B / C


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