2題代數 ,, 中一

2007-10-07 11:49 pm
1 ) 7-x/2 + 2 = 5
2 ) 7-x/4 - 3 = 1


要有步驟
更新1:

不對喔 ,, 第一題的答案是 1 第二題是-9 這是答案 但我不會算

更新2:

佢係冇括個wo ..

更新3:

1 ) (7﹣ x)/2 + 2 = 5 (7﹣x)/2 = 5﹣2 (7﹣x)/2 = 3 7﹣x = 3×2 [[ 7﹣x = 6 7﹣6 = x ]] x = 1 2)(7﹣x)/4﹣3 = 1 (7﹣x)/4 = 1+3 (7﹣x)/4 = 4 7﹣x = 4×4 7﹣x = 16 [[ 7﹣16 = x ]] x = -9 點解可以將 [[ ]] 呢d掉轉嫁 ,, 我都冇教過 ..

回答 (3)

2007-10-08 12:02 am
✔ 最佳答案
1 ) (7﹣ x)/2 + 2 = 5
(7﹣x)/2 = 5﹣2
(7﹣x)/2 = 3
7﹣x = 3×2
7﹣x = 6
7﹣6 = x
x = 1

2)(7﹣x)/4﹣3 = 1
(7﹣x)/4 = 1+3
(7﹣x)/4 = 4
7﹣x = 4×4
7﹣x = 16
7﹣16 = x
x = -9

2007-10-07 16:04:22 補充:
原因是你沒有括住因通常是先乘除,後加減若沒有括住,會令人誤會

2007-10-07 16:12:53 補充:
在書中,因為個條分數線長過7﹣x但在電腦上,通常會不用橫的分數線表達而是用「/」符號表示所以如果沒有括住曾變成7﹣x/2 2 = 5(7減2分之x在加2)
2007-10-08 12:17 am
1) 7- x/2 = 5 -2
7 -x/2 = 3
7-x = 3 *2
7 -x = 6
-x = 6-7
-x = -1
x = 1

2) 7-x/4 = 1 +3
7-x/4 = 4
7-x = 4*4
7-x = 16
-x = 16 -7
-x = 9
x = -9
2007-10-07 11:54 pm
1 ) 7-x/2 + 2 = 5
7-x/2 + 2-2=5-2
7-x/2=3
x/2=7-3
x/2=4
x/2*2=4*2
x=8
2 ) 7-x/4 - 3 = 1
7-x/4 - 3 +3=1+3
7-x/4=4
x/4=3
x/4*4=3*4
x=12


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