超簡單(急)幫幫忙 thz

2007-10-07 8:06 pm
3.若a=1 b=2 c=3 d=4 e=5 f=6 g=7 h=8 i=9 j=0 ,求下列各式的值.
a)ac+bd e+f c)i(d+2c)
b)---
h
d)(d-b)(f+c) e)ah的2次方g f)g的2次方+h的2次方+j的2次方

2(3i-b) a+b+c+d+e+f
g) --- h)f(5h的2次方-2j) i) ------
5a ghi

回答 (2)

2007-10-07 8:24 pm
✔ 最佳答案
a) ac+bde+f = 1*3+2*4*5+6 = 3+40+6 = 49

c) i(d+2c) = 9(2*3) = 9*6 = 54

d) ah的2次方g = 64*7 = 448

f) g的2次方+h的2次方+j的2次方 = 49+64 = 115

2 (3i-b) a+b+c+d+e+f = 2(3*9-2)1+2+3+4+5+6 = 70

h) f(5h的2次方-2j) = 6(5*8的2次方-2*0) = 1908

5a ghi = 7*8*9 = 504
參考: Me
2007-10-07 9:24 pm
a. ac+bd e+f
=(1)(3)+(2)(4)(5)+6
=3+40+6
=49
c. i(d+2c)
=9[4+2(3)]
=9(4+6)
=90
d. (d-b)(f+c)
=(4-2)(6+3)
=2X9
=18
e. a h^2 g
=(1) (8)^2 (7)
=64X7
=448
f. g^2 +h^2 +j^2
=(7)^2 +(8)^2 +(0)^2
=49+64
=113
參考: me


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