Indefinite Integrals
回答 (2)
2007-10-07 7:59 pm
✔ 最佳答案
Try multiply top and bottom by sqrt(x+3)-sqrt(x) to turn the expression to:( sqrt(x+3)-sqrt(x) ) / (x+3-x)
=( sqrt(x+3)-sqrt(x) ) / 3
=sqrt(x+3)/3 -sqrt(x)/3
Each of the two terms can be integrated by elementary forms, giving
I=(2/9) ( (x+3)^(3/2) - x^(3/2) )
2007-10-07 7:54 pm
anw=dx
收錄日期: 2021-04-13 13:47:40
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20071007000051KK01575