"Newton's cradle" consists usually of five small steel spheres, each suspended by two light strings. Modelling this by a no. of particles each suspended by two strings inclined at 80* to the horizontal, find the tension in each string when:
(a) the weight of each steel sphere is 0.8N
(b) the mass of each steel sphere is 0.1kg
The correct answer of (a) and (b) are 0.406N and 0.498N
Tension in each string of Newton's cradle
2007-10-07 2:04 am
回答 (2)
2007-10-07 5:20 am
✔ 最佳答案
(a) T = 0.8 / cos (90°-80°), where T is the total tension of two string.T = 0.812N
So, the tension in each string is 0.406N.
(cos 10° because a string is inclined at 80° to the horizontal, i.e. 10° to the vertical)
(b) weight = mg
= 0.1 (10) = 1N
Similar to part (a), T = 1 / cos (90°-80°) = 1.015N
So, the tension in each string is 0.508N.
(Your answer is 0.498N properly due to the value taken of g) (You took g = 9.8)
2007-10-09 10:28 am
Great!
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