F.1數學(急)Help ME!!!!

2007-10-07 12:30 am
唔該幫我計(連式):

7a-(9a-16) =14-(19-a)

Please!!!!

回答 (7)

2007-10-07 12:52 am
✔ 最佳答案
7a-(9a-16) =14-(19-a)
7a-9a+16=14-19+a
-2a+16=-5+a
16+5=a+2a
21=3a
21/3=a
7=a

所以﹕a=7
參考: me
2007-10-07 1:54 am
7a-(9a-16) = 14-(19-a)
7a-9a+16 = 14-19+a
-2a+16 = -5+a
-2a+16-16 = -5+a-16
-2a = a-21
-2a-a = a-21-a
-3a = -21
-3a/3 = -21/3
-a = -7
-a/-1 = -7/-1
a=7
2007-10-07 12:50 am
7a-(9a-16) =14-(19-a)
7a-9a+16 =14-19+a
-2a+16=-5+a
-3a=-21
a=7
解:代表7入a,
7*7-(9*7-16)=14-(19-7)
49-(63-16)=14-12
49-47=2
2=2
兩邊係相等既~
2007-10-07 12:36 am
7a-9a+16 = 14-19+a
-2a+16 = - 5+a
16=3a-5
16+5=3a
21=3a
21/3=a
a=7
2007-10-07 12:35 am
7a-(9a-16) =14-(19-a)
7a-9a+16 =14-19+a
-2a+16=-5+a
-3a=-21
a=7
2007-10-07 12:35 am
7a-(9a-16) =14-(19-a)
7a-9a+16=14-19+a
-2a+16=-5+a
16+5=a+2a
19=3a
19/3=a
a=19/3
2007-10-07 12:34 am
7a-(9a-16) =14-(19-a)
7a-9a+16 =14-19+a
-2a+16=-5+a
-3a=-21
a=7


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