中三數,三條!

2007-10-06 7:53 pm
利用代入消元法解下列聯立二元一次方程式。(要步驟)

1 .x + y + 2 = 9x - 2y = 5


2.
╭ 2x - 5y = 7

╰ 4x + 3y = 1

3.
╭ x + y = 2

╰ x  y
 - - - = 1
 2  3

回答 (1)

2007-10-06 8:06 pm
✔ 最佳答案
1:
x+y+2=5
x=5-2-y
x=3-y

9x-2y=5
9(3-y)-2y=5
27-9y-2y=5
-7y=5-27
y=-22/-7
y=22/7

x=3-y
x=3-22/7
x=-1/7

2:
2x-5y=7
2x=7+5y
x=(7+5y)/2

4x+3y=1
4(7+5y)/2+3y=1
14+10y+3y=1
13y=1-14
13y=-13
y=-1

x=(7+5y)/2
x=(7-5)/2
x=1

3:
x+y=2
x=2-y

x/2-y/3=1
(3x-2y)/6=1
3x-2y=6
3(2-y)-2y=6
6-3y-2y=6
y=0

x=2-y
x=2


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