F4 Math一問~~~~~
回答 (2)
2007-10-05 3:56 am
✔ 最佳答案
將 x^2+4x+5 除 x - 1得商 x + 5, 餘數 10
故 x^2+4x+5 = (x-1)(x+5) + 10
= (x-1)((x-1) + 6) + 10
g (x-1) = (x-1)((x-1) + 6) + 10
設 y = x-1
g (y) = (y)(y + 6) + 10
故 g(a) = (a)(a + 6) + 10
= a^2 + 6a + 10
2007-10-05 3:38 am
g(x - 1) = x2 + 4x + 5
g(x) = (x + 1)2 + 4(x + 1) + 5
g(x) = x2 + 6x + 10
g(a) = a2 + 6a + 10
g(x) = (x + 1)2 + 4(x + 1) + 5
g(x) = x2 + 6x + 10
g(a) = a2 + 6a + 10
參考: Myself~~~
收錄日期: 2021-04-13 19:21:28
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https://hk.answers.yahoo.com/question/index?qid=20071004000051KK03232