求 (ax^2 + b)^2 的導數
dy/dx = 2(ax^2 + b)(2ax)
= 4ax(ax^2 + b)
如果
設 u = (ax^2 + b)
u^2 = (ax^2 + b)^2
錦 dy/dx = d(u^2)/dx = 2u = 2(ax^2 + b)................Power Rule
點解會錦 ....... ?
Answer in Chinese will better
About Derivative
2007-10-05 2:23 am
回答 (1)
2007-10-05 3:44 am
✔ 最佳答案
你做完dy/dx = d(u^2)/dx = 2u = 2(ax^2 + b)之後你要d埋個u去
u=(ax^2+b)
du/dx=d/dx ax^2+ d/dx b
=2ax
b係constant所以0左
ax^2用左公式咪變左2ax
之後你張 2(ax^2 + b)乘2ax
咪係4ax(ax^2 + b)
希望幫到你!
參考: me
收錄日期: 2021-04-13 19:33:08
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https://hk.answers.yahoo.com/question/index?qid=20071004000051KK02606