F.2 Maths

Solution:
1. {1/[3(r+1)]} - {2/[6/(1+r)]}
={1/[3(r+1)]} - 2x[(1+r)/6]
={1/[3(r+1)]} -[(1+r)/3]
=(1/3)-(1/3)
=0

2a. -6f³+3fg+9f
=3f x -2f² + 3f x g + 3f x 3
=3f(-2f²+g+3)

2b. 2xy² + 2xy +4x^2y
=2xy² + 2xy +4(x²)(x^y)
=2x(y²)+2x(y)+2x(2x)(x^y)
=2x[y²+y+x^(y+1)]

2a.3f(-2f^2+g+3)
2b.2xy(y+1+2x)