1.When 90 minus the product of 6 and a number ,the result is 36 . Find the number .
2.When the sum of 2 times a number and 6 is divided by 3 , the result is 12 . Find the number .
F.1 maths
2007-10-04 1:51 am
回答 (5)
2007-10-04 1:55 am
✔ 最佳答案
1.Let x be the number.90﹣6x = 36
90 = 36 + 6x
54 = 6x
x = 9
2.Let x be the number.
(2x + 6) / 3 = 12
2x + 6 = 36
2x = 30
x = 15
2007-10-04 5:04 am
1)Let x be the number.
90-6x=36
90=36+6x
54=6x
x=9
2)Let x be the number.
(2x+6)/3=12
2x+6=36
2x=30
x=15
90-6x=36
90=36+6x
54=6x
x=9
2)Let x be the number.
(2x+6)/3=12
2x+6=36
2x=30
x=15
參考: me
2007-10-04 2:04 am
1.Let x be the number.
90﹣6x = 36
90 = 36 + 6x
54 = 6x
x = 9
2.Let x be the number.
(2x + 6) / 3 = 12
2x + 6 = 36
2x = 30
x = 15
90﹣6x = 36
90 = 36 + 6x
54 = 6x
x = 9
2.Let x be the number.
(2x + 6) / 3 = 12
2x + 6 = 36
2x = 30
x = 15
2007-10-04 1:58 am
1.When 90 minus the product of 6 and a number ,the result is 36 . Find the number .
90-(6*y)=36
90-6y=36
90=6y+36
6y+36=90
6y=90-36
6y=54
y=54/6
y=9
2.When the sum of 2 times a number and 6 is divided by 3 , the result is 12 . Find the number .
(2y+6)/3=12
2/3y+2=12
2/3y=12-2
2/3y=10
y=10/ 2/3
y=10*3/2
y=15
Answer:
1.9
2.15
90-(6*y)=36
90-6y=36
90=6y+36
6y+36=90
6y=90-36
6y=54
y=54/6
y=9
2.When the sum of 2 times a number and 6 is divided by 3 , the result is 12 . Find the number .
(2y+6)/3=12
2/3y+2=12
2/3y=12-2
2/3y=10
y=10/ 2/3
y=10*3/2
y=15
Answer:
1.9
2.15
參考: Me
2007-10-04 1:56 am
1. Let the number be x
90 - 6x = 36
90 - 6x + 6x = 36 + 6x
90 = 36 + 6x
90 - 36 = 6x - 36
54 = 6x
x = 9
2. Let the number be y
(2y + 6)/3 = 12
2y + 6 = 36
2y + 6 - 6 = 36 - 6
2y = 30
y = 15
90 - 6x = 36
90 - 6x + 6x = 36 + 6x
90 = 36 + 6x
90 - 36 = 6x - 36
54 = 6x
x = 9
2. Let the number be y
(2y + 6)/3 = 12
2y + 6 = 36
2y + 6 - 6 = 36 - 6
2y = 30
y = 15
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