MATHS""

2007-10-03 3:36 am
列色PLX*

1) If Ax(2次方)-x-B=(x-3)(x+C), find the values of A, B and C.

回答 (1)

2007-10-03 3:45 am
✔ 最佳答案
A x^2 -x -B =(x-3)(x+C)
A x^2 -x -B = x^2 -3x+Cx -3C
A x^2 -x -B = x^2 +(-3+C)x -3C

Compare L.H.S. and R.H.S.,
-1 = - 3+C
C = 2

-B = -3C
B =3 x 2
B = 6

A=1


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