3x的二次方-5x=2=0
之後之後係點!??
數學一元二次方程. 快快快!
2007-10-02 9:56 pm
回答 (4)
2007-10-02 10:06 pm
✔ 最佳答案
the above answer is wrong.3x^2-5x+2=0
3x^2-3x-2x+2=0
3x(x-1)-2(x-1)=0
(3x-2)(x-1)=0
x=2 or x=1
2007-10-02 14:07:31 補充：
sorry, x=2/3 or x=1
參考: me
2007-10-03 1:27 am
3x^2-5x+2=0
(3x-2)(x-1)=0
3x-2=0 or x-1=0
x=2/3 or x=1
(3x-2)(x-1)=0
3x-2=0 or x-1=0
x=2/3 or x=1
2007-10-02 11:18 pm
如果係3x的二次方,
咁就係(3x)^2唔係3x^2,
好大different ga,
(3X)^2-5X+2=0
9X^2-5X+2=0
9X^2+2=5X
(9X^2+2)/5=X
@w@
咁就係(3x)^2唔係3x^2,
好大different ga,
(3X)^2-5X+2=0
9X^2-5X+2=0
9X^2+2=5X
(9X^2+2)/5=X
@w@
參考: Me
2007-10-02 10:01 pm
3x^2 - 5x + 2 = 0
(3x+1)(x-2) = 0 (Be noted that 3(-2) - 1 = -5)
Thus,
x=-1/3 or x=2
(3x+1)(x-2) = 0 (Be noted that 3(-2) - 1 = -5)
Thus,
x=-1/3 or x=2
參考: Me
收錄日期: 2021-04-13 19:04:03
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