數學一元二次方程. 快快快!

the above answer is wrong.

3x^2-5x+2=0
3x^2-3x-2x+2=0
3x(x-1)-2(x-1)=0
(3x-2)(x-1)=0
x=2 or x=1

2007-10-02 14:07:31 補充：
sorry, x=2/3 or x=1

3x^2-5x+2=0
(3x-2)(x-1)=0
3x-2=0 or x-1=0
x=2/3 or x=1

如果係3x的二次方,
咁就係(3x)^2唔係3x^2,
好大different ga,

(3X)^2-5X+2=0
9X^2-5X+2=0
9X^2+2=5X
(9X^2+2)/5=X

@w@

3x^2 - 5x + 2 = 0
(3x+1)(x-2) = 0 (Be noted that 3(-2) - 1 = -5)
Thus,
x=-1/3 or x=2