我想問
1) y+1/6
2) (y+1)/6
係唔係一樣嫁?
1) 2/3[y(a-b)]
2) [2y(a-b)]/3
咁e個呢?
數學一問?!
2007-10-02 2:33 am
回答 (4)
2007-10-02 4:54 am
✔ 最佳答案
1) y+1/62) (y+1)/6係唔一樣既
如果將5代入去y既話
1)5+1/6=30/6+1/6=31/6
2)(5+1)/6=6/6=1
so:31/6唔等於1既
============================
1) 2/3[y(a-b)]
2) [2y(a-b)]/3
將5代入去y,4代入a,3代入b既話
1)2/3*[5*4-3)]
=2/3*[5*1]
=2/3*1
=2/3
2)[2*5*(4-3)]/3
=[2*5*1]/3
=10/3
so:2/3唔等於10/3
佢地係不同項
2007-10-02 3:07 am
no,no
2007-10-02 2:39 am
1.yes
2007-10-02 2:37 am
唔係
唔係
唔係
收錄日期: 2021-04-13 13:42:29
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20071001000051KK04338