正負數一小問

(-8y) ÷ x ÷ 2z
=(-8(5))÷(-2)÷2(-4)
= -2.5

(-20z)÷2y÷(2x)
=(-20(-4))÷2(5)÷(2(-2))
= -2

(-8y) ÷ x ÷ 2z
=-2.5
(-20z)÷2y÷(2x)
=-2

X = -2 , y = 5 , z = -4

( -8 y) ÷ x ÷ 2z
= ( -8 × 5) ÷ -2 ÷2 × -4
=( -40)÷ -2 ÷2 × -4
= +20 ÷2 × -4
= +10× -4
= -40


( -20z)÷2y÷(2x)
= (-20×-4)÷2×5÷(2×-2)
= +80÷2×5÷(2×-2)
= 40×5÷(2×-2)
= 200÷(-1)
= -200

you mean z=-4?
ifx= -2 , y= 5 , z= -4

1)(-8y)÷x ÷ 2z
=(-8X5)÷(-2)÷2(-4)
=(-40)÷(-2)÷(-8)
=(20)÷(-8)
=-5/4

2)(-20z)÷2y÷(2x)
=(-20)(-4)÷(2X5)÷(2)(-2)
=80÷10÷(-4)
=-2

x= -2 , y= 5 , z= -4

(-8y) ÷ x ÷ 2z
=(-40)÷(-2)÷(-8)
=20÷-8
=-(5/2)

(-20z)÷2y÷(2x)
=80÷10÷(-4)
=8÷(-4)
=-2

1
(-8y) ÷ x ÷ 2z
=(-8×5)÷(-2)÷(2×-4)
=(-40)÷(-2)÷(-8)
=20÷(-8)
=負2.5


2
(-20z)÷2y÷(2x)
=(-20×-4)÷(2×5)÷(2×-2)
=(80)÷(10)÷(-4)
=8÷(-4)
=負2

1) (-8y) ÷ x ÷ 2z
= (-8)(5)÷-2÷(2)(-4)
=-40÷2÷-8
=-20÷8
=-2.5

2)(-20z)÷2y÷(2x)
=(-20)(-4)÷(2)(5)÷(2)(-2)
=80÷10÷-4
=8÷-4
=-2

2007-10-01 14:00:06 補充：
其實 z=-4?

(-8y) ÷ x ÷ 2z
= -40


(-20z)÷2y÷(2x)
= -200

５知岩5岩Ｎeee??"..XD

1

-2

2007-10-01 13:58:44 補充：
錯了錯了 應該係:-2.5-2