maths equations

12-2-p/5 = 14 <- equation

10-p/5=14 <---- 12-2 = 10

-p/5=14-10 <--- put 10 to right and change + sign to - sign

-p/5 = 4 <------ 14-10=4

(-p/5)5 = 5(4) <---- times each by 5 to get rid of denomater 5

-p=20

-p /-1 = 20/-1 < to get rid of the negative

p= - 20 <--- final answer

12-2-p/5=14
-->10-p/5=14
-->10-p/5-10=14-10
-->-p/5=4
-->5(-p/5)=5(4)
-->-p=20
-->-1(-p)= -1(20)
-->p= -20

1. 12-2-p/5 = 14
12-2-p/5-12+2 = 14-12+2
p/5 x 5= 4x5
p = 20

2007-10-01 12:34:54 補充：
對不起，睇漏左個 -p/5由第三個steps開始-(p/5) x -5 = 4x(-5) p = -20咁先岩

1)

12-2-p/5 = 14

p/5 = -7

p = -35