我想問條數點計(中一的)thx

2007-10-01 3:57 am
請大家help help me
1.
0.4a - 0.2 (a-6) = 0.5

2.
y x y2 = 48
及幫我解忻一下點樣計出來(要有步x)

thx thx ^_^

回答 (2)

2007-10-01 4:12 am
✔ 最佳答案
1/

0.4a - 0.2 (a-6) = 0.5
0.4a - (0.2a - 1.2) = 0.5
0.4a - 0.2a + 1.2 = 0.5
0.2a = -0.7
a = -7/2
a = -3.5

2/

Is y2 = y (square)?
2007-10-01 5:18 am
1) 0.4a - 0.2 (a-6) = 0.5
0.4a - (0.2a - 1.2) = 0.5
0.4a - 0.2a + 1.2 = 0.5
0.2a = -0.7
a = - 7/2
a = -3.5
2) y X y2=48
y2+ y - 48 =0
y~6.45 or y~ - 7.45


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