maths
2007-10-01 1:54 am
Henry walked home from school in 30 minutes at an average speed of 60m/min.If he walked at a speed of 100m/min in the initial 1000m,what was his walking speed for the remaining journey?
回答 (3)
2007-10-01 2:03 am
✔ 最佳答案
The total distance between home and school= 30x60=1800 mif he walked at a speed of 100m/min in the initial 1000m,
he has used 10 minutes only.
Then it has 800m left.
800/20=40m/min.
therefore, his walking speed for the remaining journey is 40m/min.
參考: 自己
2007-10-01 6:34 am
(30*60-1000)/(30-1000/100)
=(1800-1000)/(30-10)
=800/20
=40
so his walking speed for yhe remaining journey is 40m/min
I want to ask you are form?
=(1800-1000)/(30-10)
=800/20
=40
so his walking speed for yhe remaining journey is 40m/min
I want to ask you are form?
參考: my experience
2007-10-01 2:06 am
journey/time=speed
60x30=900m
so the journey is 1800m
1000/t=100
t=10mins
he used 10mins to walk the initial 1000m
if he walking home is in 30mins..so he must use 20mins to walk 800m..
800/20=40m/min
the anwer is 40m/min
60x30=900m
so the journey is 1800m
1000/t=100
t=10mins
he used 10mins to walk the initial 1000m
if he walking home is in 30mins..so he must use 20mins to walk 800m..
800/20=40m/min
the anwer is 40m/min
收錄日期: 2021-04-25 15:39:11
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