F.2 MATHS

2007-09-30 11:51 pm
Q1.
1/x-1 - 1/x
Q2
x/x+y + y/x-y


STEPS PLEASE
更新1:

WHY [x-(x-1)]?

回答 (1)

2007-10-01 12:07 am
✔ 最佳答案
1. 1/x-1-1/x
=x(1)/x(x-1)-1(x-1)/x(x-1)
=x/x(x-1)-x+1/x(x-1) 找最小公倍數
=1/x(x-1)
2.x/x+y +y/x-y
=x(x-y)/(x+y)(x-y) +y(x+y)/(x+y)(x-y)
=x^2-xy/(x+y)(x-y)+xy+y^2/(x+y)(x-y) Don't expand the denominator
=x^2+y^2/(x+y)(x-y)

唔知對不對,自己驗算


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