唔該列[[[中間既計算過程]]]比我!!!
/ = 除
1) (+11) - (-2) x [(+6) / (-3) + (-2)] = (+3)
2) [(+2/3) + (- 5/3) - (-3/2)] / [(- 1/2 + 1/3) x (-6)] = (+ 1/2)
第2題係分數!!!
我用中文打多一次...
2) [(正3分之2) 加 (負3分之5)] 除以 [(負2分之1 加 正3分之1) 乘以 (負6)] = (正2分之1)
正負數四則運算(2題)!!!10分...10月1日或之前回答我們!!
2007-09-30 5:11 pm
回答 (3)
2007-09-30 5:45 pm
✔ 最佳答案
1.=+11- (-2) x [-(6 ÷3) -2)] =+11+2×(-4)
=+11-(2×4)
=+11-8
2.=(+2/3 - 5/3 + 3/2)/ [ (- 1/2 + 1/3) x (-6)]
=+(1/2)× [-(1/6)×(-6)]
=+(1/2)×(+1)
=+(1/2×1)
2007-10-01 7:21 am
1)=11+2x[(-2)-2]=3
=11+2x[-4]=3
=11-8=3
2)=[4/6-10/6+9/6]/[(-3/6+2/6)x(-6)]=1/2
=3/6/[1]=1/2
=1/2
=11+2x[-4]=3
=11-8=3
2)=[4/6-10/6+9/6]/[(-3/6+2/6)x(-6)]=1/2
=3/6/[1]=1/2
=1/2
參考: me
2007-09-30 5:28 pm
1)
(+11) - (-2) x [(+6) / (-3) + (-2)]
= (+11) - (-2) x [ (-2) -2 ]
= (+11) - (-2) x (-4)
= (+11) - (+8)
= (+11) - 8
= (+3)
2)
[(+2/3) + (- 5/3) - (-3/2)] / [(- 1/2 + 1/3) x (-6)]
= [(-3/3) - (-3/2)] / [ (-1/6) * (-6) ]
= [(-1)-(-3/2)] / (1)
= [(-2/2) + (3/2)]
= (+1/2)
(+11) - (-2) x [(+6) / (-3) + (-2)]
= (+11) - (-2) x [ (-2) -2 ]
= (+11) - (-2) x (-4)
= (+11) - (+8)
= (+11) - 8
= (+3)
2)
[(+2/3) + (- 5/3) - (-3/2)] / [(- 1/2 + 1/3) x (-6)]
= [(-3/3) - (-3/2)] / [ (-1/6) * (-6) ]
= [(-1)-(-3/2)] / (1)
= [(-2/2) + (3/2)]
= (+1/2)
收錄日期: 2021-04-13 19:16:57
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070930000051KK00856