中學數學(20分)

2007-09-29 6:48 pm
e條數學,要列名過程
5(y+4)-6(8+3y)=-2

答案係-2,但我要過程

回答 (4)

2007-09-29 6:51 pm
✔ 最佳答案
5(y+4)-6(8+3y)=-2
5y+20-48-18y=-2
20-48+2=18y-5y
-26=13y
y=-2
2007-09-29 6:57 pm
5y+20-48-18y=-2
5y-18y= -2+48-20
-13y=26
y=-2
2007-09-29 6:54 pm
5y+20-48-18y=-2
-13y-28=-2
-13y=26
y=26/-13
y=-2
2007-09-29 6:53 pm
5(y+4)-6(8+3y)=-2
5y+20-(48+18y)=-2
5y+20-48-18y=-2
5y-18y=-2-20+48
-13y=26
y=26/-13
y=-2


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