f.2 mathssssss 急急急急急

2007-09-29 6:33 pm
f.2 mathssssss 急急急急急
1. (x/2 +2 )^2
=?
=?

2. (3p/4 +2 )^2
=?
=?

3. 4(x/2 +1) (x/2 -1)
=?
=?

4. 2(y/2 +1)(2-y)
=?
=?

5. (y+1)^2 + (1-y)^2
=?

回答 (2)

2007-09-29 6:41 pm
✔ 最佳答案
1. (x/2 + 2)2

= (x/2)2 + 2(x/2)(2) + 22

= x2/4 + x/2 + 4

2. (3p/4 + 2)2

= (3p/4)2 + 2(3p/4)(2) + 22

= 9p2/16 + 3p + 4

3. 4(x/2 + 1)(x/2 - 1)

= 4[(x/2)2 - 12]

= 4(x2/4 - 1)

= x2 – 4

4. 2(y/2 + 1)(2 - y)

= (y + 2)(2 - y)

= (2 + y)(2 - y)

= 22 – y2

= 4 – y2

5. (y + 1)2 + (1 - y)2

= (y + 1)2 + [-(y - 1)]2

= (y + 1)2 + (y - 1)2

= (y2 + 2y + 1) + (y2 – 2y + 1)

= 2y2 + 2
參考: Myself~~~
2007-09-29 6:42 pm
use formula: (a+b)^2=a^2+2ab+b^2 and (a-b)^2=a^2-2ab+b^2

then you can do it...


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