✔ 最佳答案
It is not common to specifiy gamma ray energy in terms of temperature. But if you prefer, you may use the following equation which is used to describe the kinetic temperature of molecules,
E=hf = (3/2)kT
where E is the energy of gamma ray photon
h is Planck's constant (= 6.6x10^-34 J.s)
f is the frequency of gamma ray photon
k is Boltzmann's constant (= 1.38x10^-23 J/K)
T is the absolute temperature
For example, for gamma ray photons of 1.33 MeV emitted from a Cobalt-60 radioactive source,
E = 1.33 x 10^6 x 1.6 x 10^-19 J
T = 2E/3k = 2x1.33x10^6x1.6x10^-19/(3x1.38x10^-23) K
= 10^10 K (i.e. 10 billion degrees)
As a comparison, visible light is of temperature around 17,000 K