5[2(y-4.2)+y-1]=y-5
諗唔到
呢條數點計(5)
2007-09-28 5:28 am
回答 (9)
2007-09-28 5:32 am
✔ 最佳答案
5[2(y-4.2)+y-1]=y-55(2y-8.4+y-1)=y-5
10y-42+5y-5=y-5
10y+5y-y=-5+5+42
14y=42
y=42/14
y=3
Answer: 3
2007-09-27 22:00:33 補充：
Don't copy me!
參考: Me
2007-09-29 5:06 am
5[2(y-4.2)+y-1] = y-5
5[(2y-8.4)+y-1] = y-5
5[2y-8.4+y-1] = y-5
10y-42+5y-5 = y-5
10y-42+5y-5 = y-5
10y+ 5y-y = (-5)+42+5
15y-y = 37+5
14y = 42
14y÷14 = 42÷14
y = 3
..........ok.......
5[(2y-8.4)+y-1] = y-5
5[2y-8.4+y-1] = y-5
10y-42+5y-5 = y-5
10y-42+5y-5 = y-5
10y+ 5y-y = (-5)+42+5
15y-y = 37+5
14y = 42
14y÷14 = 42÷14
y = 3
..........ok.......
2007-09-28 7:29 am
5[2(y-4.2)+y-1]=y-5
5[2y-8.4+y-1]=y-5
5[2y+y-8.4-1]=y-5
5[3y-9.4]=y-5
15y-47=y-5
15y-y=-5+47
14y=42
y=3
5[2y-8.4+y-1]=y-5
5[2y+y-8.4-1]=y-5
5[3y-9.4]=y-5
15y-47=y-5
15y-y=-5+47
14y=42
y=3
參考: Myself
2007-09-28 5:40 am
5[2(y-4.2)+y-1]=y-5
5(2y-8.4+y-1) =y-5
5(3y-9.4) =y-5
15y-47=y-5
14y=42
y=3
5(2y-8.4+y-1) =y-5
5(3y-9.4) =y-5
15y-47=y-5
14y=42
y=3
2007-09-28 5:40 am
5[2(y-4.2)+y-1]=y-5
5(2y-8.4+y-1)=y-5
10y-42+5y-5=y-5
10y+5y-y=-5+5+42
14y=42
y=42/14
y=3
Answer: 3
5(2y-8.4+y-1)=y-5
10y-42+5y-5=y-5
10y+5y-y=-5+5+42
14y=42
y=42/14
y=3
Answer: 3
參考: kuku
2007-09-28 5:40 am
5[2(y-4.2)+y-1]=y-5
5(2y-8.4+y-1)=y-5
10y-42+5y-5=y-5
10y+5y-y=-5+5+42
14y=42
y=42/14
y=3
5(2y-8.4+y-1)=y-5
10y-42+5y-5=y-5
10y+5y-y=-5+5+42
14y=42
y=42/14
y=3
參考: do it myself
2007-09-28 5:34 am
5[2(y-4.2)+y-1]=y-5
5[2y-8.4+y-1]=y-5
10y-42+5y-5=y-5
10y+5y-y=-5+42+5
14y=42
y=3
5[2y-8.4+y-1]=y-5
10y-42+5y-5=y-5
10y+5y-y=-5+42+5
14y=42
y=3
參考: 比我啦
2007-09-28 5:33 am
5[2(y-4.2)+y-1]=y-5
5(2y-8.4+y-1)=y-5
10y-42+5y-5=y-5
10y+5y-y=-5+5+42
14y=42
y=42/14
y=3
Answer: 3
5(2y-8.4+y-1)=y-5
10y-42+5y-5=y-5
10y+5y-y=-5+5+42
14y=42
y=42/14
y=3
Answer: 3
收錄日期: 2021-04-13 13:39:21
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070927000051KK04064