/=分數線
(IDENTITIES)
x+1/3+2x-1/6=4x+7/6-1
LHS=
RHS=
Is it a identity?
Maths
2007-09-28 5:02 am
回答 (3)
2007-09-28 5:40 am
✔ 最佳答案
L.H.S. = x+1/3+2x-1/6
= x + 2x + 2/6 - 1/6
= 3x + 1/6
R.H.S.
= 4x + 7/6 - 1
= 4x + 7/6 - 6/6
= 4x + 1/6
Since
3x + 1/6 = 4x + 1/6
3x = 4x
3x - 4x = 0
-x = 0
x = 0
x has only ONE solution.
It cannot be satisfied for ALL values of x
Thus it is NOT an identity
2007-09-28 5:33 am
x+1/3+2x-1/6=4x+7/6-1
L.H.S=3x+1/3-1/6
=3x+1/6
R.H.S=4x+7/6-1
=4x+1/6
because 3x+1/6 is not equal to 4x+1/6
L.H.S is not equal to R.H.S
so x+1/3+2x-1/6=4x+7/6-1 is not an identity.
L.H.S=3x+1/3-1/6
=3x+1/6
R.H.S=4x+7/6-1
=4x+1/6
because 3x+1/6 is not equal to 4x+1/6
L.H.S is not equal to R.H.S
so x+1/3+2x-1/6=4x+7/6-1 is not an identity.
2007-09-28 5:06 am
x+1/3+2x-1/6=4x+7/6-1
LHS= 3x + 1/6
RHS= 4x + 1/6
Therefore, it is not an identity.
LHS= 3x + 1/6
RHS= 4x + 1/6
Therefore, it is not an identity.
參考: myself
收錄日期: 2021-04-13 13:39:20
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070927000051KK03836