Maths

L.H.S.
= x+1/3+2x-1/6
= x + 2x + 2/6 - 1/6
= 3x + 1/6

R.H.S.
= 4x + 7/6 - 1
= 4x + 7/6 - 6/6
= 4x + 1/6

Since
3x + 1/6 = 4x + 1/6
3x = 4x
3x - 4x = 0
-x = 0
x = 0

x has only ONE solution.
It cannot be satisfied for ALL values of x
Thus it is NOT an identity

x+1/3+2x-1/6=4x+7/6-1

L.H.S=3x+1/3-1/6
=3x+1/6
R.H.S=4x+7/6-1
=4x+1/6
because 3x+1/6 is not equal to 4x+1/6
L.H.S is not equal to R.H.S
so x+1/3+2x-1/6=4x+7/6-1 is not an identity.

x+1/3+2x-1/6=4x+7/6-1

LHS= 3x + 1/6

RHS= 4x + 1/6

Therefore, it is not an identity.