１）7k-(9k-16)=14-(19-k)
２）3[4(2.5-q)+1]=13-2q
我要條式！！
唔該哂！！
中一數學(方程)
2007-09-28 3:31 am
回答 (10)
2007-09-28 3:40 am
✔ 最佳答案
１）7k-(9k-16) = 14-(19-k)
7k-9k+16 = 14-19+k
-2k+16 = -5+k
21 = 3k
k = 7
２）
3[4(2.5-q)+1] = 13-2q
12(2.5-q)+3 = 13-2q
30-12q = 10-2q
20 = 10q
q = 2
希望幫到你~
參考: me
2007-09-28 3:47 am
1) 7k-(9k-16)=14-(19-k)
7k-9k+16=14-19+k
16-14+19=k+9k
21=3k
k=7
2) 3[4(2.5-q)+1]=13-2q
3[(10-4q)+1]=13-2q
3(11-4q)=13-2q
33-12q=13-2q
20=10q
2=q
唔知你係咪想要呢d式呢?希望幫到你la!!!
7k-9k+16=14-19+k
16-14+19=k+9k
21=3k
k=7
2) 3[4(2.5-q)+1]=13-2q
3[(10-4q)+1]=13-2q
3(11-4q)=13-2q
33-12q=13-2q
20=10q
2=q
唔知你係咪想要呢d式呢?希望幫到你la!!!
參考: 自己
2007-09-28 3:47 am
7k-(9k-16)=14-(19-k)
7k-9k+16=14-19+k
7k-9k-k=14-19-16
-3k=-21
k=7
3[4(2.5-q)+1]=13-2q
3(10-4q+1)=13-2q
30-12q+1=13-2q
-12q+2q=13-30-1
10q=-28
q=-28over10
7k-9k+16=14-19+k
7k-9k-k=14-19-16
-3k=-21
k=7
3[4(2.5-q)+1]=13-2q
3(10-4q+1)=13-2q
30-12q+1=13-2q
-12q+2q=13-30-1
10q=-28
q=-28over10
參考: 自己
2007-09-28 3:46 am
1, 7k-9k-16=14-19-k
-2k+k=14+16-19
-k=11
k=-11
2, 3(10-4q+1)=13-2q
30-12q+3=13-2q
-12q+2q=13-30-3
-10q=--20
q=2
-2k+k=14+16-19
-k=11
k=-11
2, 3(10-4q+1)=13-2q
30-12q+3=13-2q
-12q+2q=13-30-3
-10q=--20
q=2
2007-09-28 3:44 am
1) 7k-(9k-16)=14-(19-k)
--> 7k-9k+16= 14-19+k
--> -2k+16=-5+k
--> -2k-k= -5-16
--> -3k=-21
--> k=7
2) 3[4(2.5-q)+1]=13-2q
--> 3[10-4q+1]= 13-2q
--> 30-12q+3 =13-2q
--> 33 -13 = -2q +12q
--> 20 = 10q
--> q = 2
--> 7k-9k+16= 14-19+k
--> -2k+16=-5+k
--> -2k-k= -5-16
--> -3k=-21
--> k=7
2) 3[4(2.5-q)+1]=13-2q
--> 3[10-4q+1]= 13-2q
--> 30-12q+3 =13-2q
--> 33 -13 = -2q +12q
--> 20 = 10q
--> q = 2
2007-09-28 3:43 am
2) 3(10-4q+1) = 13-2q
30-12q+3 = 13-2q
-12q+2q = 13-3-30
-10q = -20
q = -20/-10
q = 2
30-12q+3 = 13-2q
-12q+2q = 13-3-30
-10q = -20
q = -20/-10
q = 2
2007-09-28 3:42 am
１
7k-(9k-16)=14-(19-k)
7k-9k+16=14-19+k
16+19-14=k+9k-7k
21=3k
k=7
２
3[4(2.5-q)+1]=13-2q
3(10-4q+1)=13-2q
30-12q+3=13-2q
33-13= (-2q)+12q
10q=20
q=2
7k-(9k-16)=14-(19-k)
7k-9k+16=14-19+k
16+19-14=k+9k-7k
21=3k
k=7
２
3[4(2.5-q)+1]=13-2q
3(10-4q+1)=13-2q
30-12q+3=13-2q
33-13= (-2q)+12q
10q=20
q=2
參考: 自己
2007-09-28 3:40 am
１）7k-(9k-16)=14-(19-k)
7k-9k+16=14-19+k
-3k=-21
k=7
２）3[4(2.5-q)+1]=13-2q
3[10-4q+1]=13-2q
3[11-4q]=13-2q
33-12q=13-2q
-10q=-20
q=2
7k-9k+16=14-19+k
-3k=-21
k=7
２）3[4(2.5-q)+1]=13-2q
3[10-4q+1]=13-2q
3[11-4q]=13-2q
33-12q=13-2q
-10q=-20
q=2
2007-09-28 3:39 am
7k-(9k-16)=14-(19-k)
7k-9k+16=14-19+k
7k-9k+k=14+16
k=30
7k-9k+16=14-19+k
7k-9k+k=14+16
k=30
2007-09-28 3:36 am
7k-(9k-16)=14-(19-k)
7k-9k+16=14-19+k
7k-9k+k=14+16
-k=30
7k-9k+16=14-19+k
7k-9k+k=14+16
-k=30
收錄日期: 2021-04-13 13:39:18
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070927000051KK03097