中一數學(方程)

１）
7k-(9k-16) = 14-(19-k)
7k-9k+16 = 14-19+k
-2k+16 = -5+k
21 = 3k
k = 7


２）
3[4(2.5-q)+1] = 13-2q
12(2.5-q)+3 = 13-2q
30-12q = 10-2q
20 = 10q
q = 2


希望幫到你~

1) 7k-(9k-16)=14-(19-k)
7k-9k+16=14-19+k
16-14+19=k+9k
21=3k
k=7

2) 3[4(2.5-q)+1]=13-2q
3[(10-4q)+1]=13-2q
3(11-4q)=13-2q
33-12q=13-2q
20=10q
2=q

唔知你係咪想要呢d式呢?希望幫到你la!!!

7k-(9k-16)=14-(19-k)
7k-9k+16=14-19+k
7k-9k-k=14-19-16
-3k=-21
k=7


3[4(2.5-q)+1]=13-2q
3(10-4q+1)=13-2q
30-12q+1=13-2q
-12q+2q=13-30-1
10q=-28
q=-28over10

1, 7k-9k-16=14-19-k
-2k+k=14+16-19
-k=11
k=-11

2, 3(10-4q+1)=13-2q
30-12q+3=13-2q
-12q+2q=13-30-3
-10q=--20
q=2

1) 7k-(9k-16)=14-(19-k)
--> 7k-9k+16= 14-19+k
--> -2k+16=-5+k
--> -2k-k= -5-16
--> -3k=-21
--> k=7

2) 3[4(2.5-q)+1]=13-2q
--> 3[10-4q+1]= 13-2q
--> 30-12q+3 =13-2q
--> 33 -13 = -2q +12q
--> 20 = 10q
--> q = 2

2) 3(10-4q+1) = 13-2q
30-12q+3 = 13-2q
-12q+2q = 13-3-30
-10q = -20
q = -20/-10
q = 2

１
7k-(9k-16)=14-(19-k)
7k-9k+16=14-19+k
16+19-14=k+9k-7k
21=3k
k=7
２
3[4(2.5-q)+1]=13-2q
3(10-4q+1)=13-2q
30-12q+3=13-2q
33-13= (-2q)+12q
10q=20
q=2

１）7k-(9k-16)=14-(19-k)
7k-9k+16=14-19+k
-3k=-21
k=7

２）3[4(2.5-q)+1]=13-2q
3[10-4q+1]=13-2q
3[11-4q]=13-2q
33-12q=13-2q
-10q=-20
q=2

7k-(9k-16)=14-(19-k)
7k-9k+16=14-19+k
7k-9k+k=14+16
k=30

7k-(9k-16)=14-(19-k)
7k-9k+16=14-19+k
7k-9k+k=14+16
-k=30