Remainder theo.

2007-09-28 3:27 am
Let f(x) = x^99+k

a)When f(x) is divided by x+1, the remainder is k. Find the value of k

b)Hence, find the remainder when 9^99 is divied by 10

回答 (1)

2007-09-28 3:42 am
✔ 最佳答案
There may be a mistake in question (a)
a)
f(x)=x^99+k
f(-1)=1
(-1)^99+k=1
k-1=1
k=2

b)
Let Q(x) be the quotient.
9^99+2=Q(x)(x+1)+1
9^99=Q(x)(9+1)-1
9^99=Q(x)(10)-1
So, the remainder=-1
i.e. the remainder=10-1=9

2007-09-27 19:44:02 補充:
a)When f(x) is divided by x 1, the remainder is 1. Find the value of k.

2007-09-27 19:45:02 補充:
If you still don't understand, please contact me.


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