maths f1

If w is the smallest number, the next two consecutive number must be w+1 and w+2
Thus,
Sum = w + (w+1) + (w+2)
= w + w + 1 + w + 2
= 3w + 3
= 3(w+1)

2007-09-28 00:35:21 補充：
如果 w 是三個連續數中最小的話其餘兩個必定是 w 1 和 w 2於是...三個數的總和 = w w 1 w 2= 3w 3抽 common factor= 3(w 1)