Maths功課help!!!!!

第一項 = 1 = 1^3

第二項 = 8 = 2^3

第三項 = 27 = 3^3

第四項 = 64 = 4^3

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如此類推，通項 = n^3


所以，數列為

1 , 8 , 27 , 64 , 5^3 , 6^3 , 7^3, 8^3, 9 ^3

= 1 , 8 , 27 , 64 ,125, 216, 343 , 512 , 729

1,8,27,64,...如些規律一直到弟九個數

請詳列計算過程

1=1x1x1=1^3

8=2x2x2=2^3

27=3x3x3=3^3

64=4x4x4=4^3

125=5x5x5=5^3

216=6x6x6=6^3

343=7x7x7=7^3

512=8x8x8=8^3

729=9x9x9=9^3

1 是 1 的3次
8 是 2 的3次
27是3 的3次
64是4 的3次
如此類推...
第9個數是9 的3次,即是729
hope this can help u

1 = 1x1x1
8 = 2x2x2
27 = 3x3x3
64 = 4x4x4
125= 5x5x5
216=6x6x6
343=7x7x7
512=8x8x8
729=9x9x9

1 x 1 x 1 = 1
2 x 2 x 2 = 8
3 x 3 x 3 = 27
4 x 4 x 4 = 64
5 x 5 x 5 = 125
6 x 6 x 6 = 216
7 x 7 x 7 = 343
8 x 8 x 8 = 512
9 x 9 x 9 = 729
10 x 10 x 10 = 1000

The sequence is the third power of all natural numbers (1, 2, 3, ...)

The first nine numbers are 1^3, 2^3, ..., 9^3

That is, 1, 8, 27, 64, 125, 216, 343, 512, 729.