36x(-1^2)-[(-4)+-(27)=?
請列步驟~!
maths!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
2007-09-27 4:37 am
回答 (2)
2007-09-28 4:01 am
✔ 最佳答案
36x(-1^2)-[(-4)+-(27)=?=36x1-(-31)
=36+31
=67
36x(-1^2)-[(-4)+-(27)=67
參考: 自己,無用計數機嫁
2007-09-27 4:42 am
唔知你有冇打錯.....^.^
如果係...-(1)^2
36x(-1^2)-[(-4)+-(27)]
=36(-1)-(-4-27)
=-36-(-31)
=-36+31
=-5
如果係....(-1)^2
36x(-1^2)-[(-4)+-(27)]
=36(1)-(-4-27)
=36-(-31)
=36+31
=67
如果係...-(1)^2
36x(-1^2)-[(-4)+-(27)]
=36(-1)-(-4-27)
=-36-(-31)
=-36+31
=-5
如果係....(-1)^2
36x(-1^2)-[(-4)+-(27)]
=36(1)-(-4-27)
=36-(-31)
=36+31
=67
收錄日期: 2021-04-13 13:57:12
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070926000051KK05066