1 . The prower of ferrari 430 is huge . If it accelerates from rest along a straight lne,its maximum acceleration is about 6.5 m s^ -2 . What is the shortest time it takes to accelerate from rest to 100 km h^-1 ?
(Hints:Convert the final velocity from km h^-1 into m s^-1)
physics Speed and Velocity
2007-09-27 3:11 am
回答 (2)
2007-09-27 3:33 am
✔ 最佳答案
This is a standard mechanics question on consolidationWe use the following equation:
v = u + at
1.
Now, 100 kmh^-1 = 100*1000/3600 = 250/9 ms^-1
So, 250/9 = 0 + (6.5)(t)
This follows t = 500/117 = 4.27 ms^-1
Hope the above information helps you =)
By 小儒
2007-09-27 3:40 am
acceleration = (final speed - initial speed ) / time
let t be the time needed
100 km h^-1 = 27.78 m s^-1
so,
6.5=(27.78 - 0) / t
t=4.274 second
the shortest time it takes is about 5 seconds.
hope it can help you =)
let t be the time needed
100 km h^-1 = 27.78 m s^-1
so,
6.5=(27.78 - 0) / t
t=4.274 second
the shortest time it takes is about 5 seconds.
hope it can help you =)
參考: myself
收錄日期: 2021-04-13 13:37:41
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https://hk.answers.yahoo.com/question/index?qid=20070926000051KK04503