F.1數學題(20)

2007-09-27 12:26 am
要部驟~

1.(+15)x(-8)+(-6)

2.(+6)+(+52)除(-13)

3.(+12分之5)x(-3)+(-2又8分之1)

4.(+3)分之(-8)除(-6)分之(-24)-(-3)分之(-2)

回答 (4)

2007-09-27 1:04 am
1. (+15)x(-8)+(-6)
= -120+(-6)
= -126
2.(+6)+(+52)除(-13)
=(+6)+(-4)
=2
3.(+12分之5)x(-3)+(-2又8分之1)
= -1又4分1x(-3)+(-2又8分之1)
= 3又4分3+(-2又8分之1)
= -5又8分之7
4.(+3)分之(-8)除(-6)分之(-24)-(-3)分之(-2)
= (-3分之-2) - (-3分之-2)
= 0

2007-09-26 17:06:50 補充:
I am also F.1
參考: Me
2007-09-27 12:53 am
1.(+15)x(-8)+(-6)
= -120+(-6)
= -120-6
= -126


2. (+6)+(+52)/(-13)
=(+6)+(-4)
=+6-4
=2


3..(+12分之5)x(-3)+(-2又8分之1)
  5        1
+________(3)+2_____________
   12         8

=    5      1
  ________ +2_______________
   4       8

=   10         1
 ______________ +2__________
   8          8

=   11
2 _______
  8

=   3
3 _______
  8


第4係好明你說什麼?是這樣嗎?

     -8     (-24)      -2
 ________ / __________--- __________
    +3       -6      -3
參考: ME,5知對不對的!
2007-09-27 12:52 am
1.(+15)x(-8)+(-6)
=(-120)+(-6)
=(-126)

2.(+6)+(+52)除(-13)
=(+6)+(-4)
=(+2)

3.(+12分之5)x(-3)+(-2又8分之1)
=(-4分之5)+(-2又8分之1)
=(-8分之10)+(-2又8分之1)
=(-2又8分之11)
=(-3又8分之3)

4.(+3)分之(-8)除(-6)分之(-24)-(-3)分之(-2)
=(+3)分之(-8)除6分之24-3分之2
=(+1)分之(-8)x24分之2-3分之2
=24分之(-16)-3分之2
=24分之(-16)-24分之16
=24分之(-32)
參考: myself
2007-09-27 12:44 am
1.(+15)x(-8)+(-6)
= (-120)+(-6)
= (-120)-6
= -126

2.(+6)+(+52)/(-13)
= (+6)+(-4)
= 6-4
= 2

3.(+5/12)*(-3)+(-17/8)
= (-5/4)+(-17/8)
= (-5/4)*1+(-17/8)
= (-5/4)*(2/2)+(-17/8)
= (-10/8)-(17/8)
= -27/8

4.(-8/3)/(-24/-6)-(-2/-3)
= (-8/3)/(4)-(-2/-3)
= (-8/3)*(1/4)-(-2/-3)
= (-2/3)-(-2/-3)
= (-2/3)-(2/3)
= -4/3

2007-09-26 16:48:59 補充:
2樓.,第4題係除唔係乘點解大家唔用caltor ne?
參考: me


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