plz help me to answer the question,if you do not know the answer,plz answer no~i need the step .Thank for your help~
Make the letter in the brackets the subject of each of the folllowing formulae.
1) 1/a+2/a=3/b [b]
2) b/a-1/a=4 [b]
3) y=2/3x+1/x [x]
4) y=1/5x-1/x [x]
5) y=1/2x-1/5x [x]
6) 1/a+1/b=b/a [a]
F.2 mathz very vert important~help me plz
2007-09-26 8:36 am
回答 (3)
2007-09-26 8:55 am
✔ 最佳答案
1) 1/a+2/a=3/b =>b+2b=3a
=>3b=3a
=>b=a//
2) b/a-1/a=4 ; [b]
=>ab-a=4a
=>ab=5a
=>b=5//
3) y=2/3x+1/x &nbs p; [x]
=>3xy=2+3
=>x=5/3y//
4) y=1/5x-1/x &nbs p; [x]
=>5xy=1-5
=>5xy=-4
=>x= -4/5y//
5) y=1/2x-1/5x &nb sp; [x]
=> 10xy=5-2
=>x=3/10y//
6) 1/a+1/b=b/a &nb sp; [a]
=>b+a=a^2 b
=> b=a^2 b-a
=>b=a(ab-1)
=> a=b/(ab-1)//
2007-09-26 8:44 am
1) a(1/a+2/a)=(3/b)a
3=3a/b
b=a
2) b/a=4+1/a
b=4a+1
3) 咩係  ?
3=3a/b
b=a
2) b/a=4+1/a
b=4a+1
3) 咩係  ?
2007-09-26 8:43 am
1)b=a
2)4a+1
之後o個o的唔明你講咩...
 ???
2)4a+1
之後o個o的唔明你講咩...
 ???
收錄日期: 2021-04-13 13:37:03
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