a-maths!!!!!!!

2007-09-26 6:53 am
一船在河流中逆流行駛36km,然後折回原地。已知前往時所需的時間比回程多1小時,若水流的速度為3km/h,試求該船在靜水中的速度。

回答 (1)

2007-09-26 6:56 am
✔ 最佳答案
Let the speed of the boat in still water be x km / h.
In the upstream journey, the speed of the boat: ( x – 3 ) km / h
In the downstream journey, the speed of the boat: ( x + 3 ) km / h
Then,
36 / ( x - 3 ) – 36 / ( x + 3 ) = 1
36 ( x + 3 ) – 36 ( x -3 ) = ( x + 3 )( x – 3 )
36 ( x – 3 – x + 3 ) = x2 – 9
216 = x2 – 9
x2 = 225
x = 15 or –15 ( rejected )


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